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  1. Find the point on the x-axis which is equidistant from points (2,-5 ...

    Feb 4, 2024 · Answer: The point on the x-axis is (7, 0) which is equidistant from points (2, - 5) and (- 2, 9). Step-by-step explanation: We have to find the point on the x-axis which is equidistant from the …

  2. Find a relation between x and y such that the point P (x, y) is ...

    Nov 20, 2024 · Find a relation between x and y such that the point P (x, y) is equidistant from the points A (7, 1) and B (3, 5)… Get the answers you need, now!

  3. P (-2, 5) and Q (2, -1) are two points on the coordinate ... - Brainly

    Mar 8, 2024 · The given equation represents the locus of points equidistant from P (-2, 5) and Q (2, -1). However, this locus is not a single point, but a line passing through the midpoint (0, 2) which is …

  4. ii) iii) The magnetic field in a region is represented by equidistant ...

    Oct 2, 2024 · Equidistant parallel magnetic field lines indicate that the magnetic field is uniform in the region. A uniform magnetic field means the field strength and direction are the same at every point …

  5. p is a point equidistant from two lines l and m intersecting at point A ...

    Dec 23, 2024 · Then: d_1 = d_2 Step 2: Geometric properties of angle bisectors In geometry, a point equidistant from two intersecting lines lies on the angle bisector of the angle formed by those lines. …

  6. Prove that the chords equidistant from the centre of a circle ... - Brainly

    Oct 31, 2024 · Answer: To prove that chords equidistant from the center of a circle are equal in length, we can follow these steps: Given: A circle with center . Two chords and that are equidistant from the …

  7. Determine the coordinates of a point which is equidistant ... - Brainly

    Nov 30, 2020 · Determine the coordinates of a point which is equidistant from the point (1,2) and (3,4) and the shortest distance from the line joining the points (1,2) and (3,4) to the required point is √2 .

  8. P (-2, 5) and Q (2, -1) are two points on the coordinate ... - Brainly

    Sep 17, 2023 · This is true because the midpoint of two points on a coordinate plane is the unique point equidistant from those two points. (R) states that there are many points (x, y) where are equidistant …

  9. find the locus of the point which is equidistant from A (3, 4 ... - Brainly

    Apr 3, 2024 · To find the locus of the point equidistant from points A (3, 4, 0) and B (5, 2, -3), we first need to find the midpoint of line segment AB. Then, the locus of the point equidistant from A and B …

  10. Radius of circumcircle of a triangle abc is 5 root 10 units

    Feb 8, 2023 · As P is the equidistant point from all the vertices of the triangle ABC, P is the circumcenter. Then AP is the line joining the vertex A and the circumcenter P, so AP itself is the …