A C++ question, I know int* foo (void) foo will return a pointer to int type how about int &foo (void) what does it return? Thank a lot!

Jan 28, 2012 · The real reason that this can happen is that C is a weakly typed language. But unsigned int and int are really different.

64 I prefer int* i because i has the type "pointer to an int", and I feel this makes it uniform with the type system. Of course, the well-known behavior comes in, when trying to define multiple …

Dec 30, 2011 · int a = 5; int& b = a; b = 7; cout << a; prints out 7, and replacing int& b with int &b also prints out 7. In fact so does int&b and int & b. I tested this kind of behavior with a simple …

int is a primitive data type while Integer is a Reference or Wrapper Type (Class) in Java. after java 1.5 which introduce the concept of autoboxing and unboxing you can initialize both int or …

In C#, int and Int32 appear to be the same thing, but I've read a number of times that int is preferred over Int32 with no reason given. Are the two really the same? Is there a reason …

7 c is a double variable, but the value being assigned to it is an int value because it results from the division of two int s, which gives you "integer division" (dropping the remainder). So what …

Dec 17, 2013 · │int││int││int││int││int││int││ └───┘└───┘└───┘└───┘└───┘└───┘└┄ Of course, there's no reason they can't all …

Apr 21, 2011 · 29 int and unsigned int are two distinct integer types. (int can also be referred to as signed int, or just signed; unsigned int can also be referred to as unsigned.) As the names …

Dec 29, 2022 · For INT and other numeric types that attribute only specifies the display width. See Numeric Type Attributes in the MySQL documentation: MySQL supports an extension for …