
summation - Sum of 1 + 1/2 - Mathematics Stack Exchange
How do I calculate this sum in terms of 'n'? I know this is a harmonic progression, but I can't find how to calculate the summation of it. Also, is it an expansion of any mathematical function? 1 ...
summation - The idea behind the sum of powers of 2
Oct 29, 2016 · I know that the sum of powers of $2$ is $2^{n+1}-1$, and I know the mathematical induction proof. But does anyone know how $2^{n+1}-1$ comes up in the first place. For …
summation - How to prove a formula for the sum of powers of …
Mar 8, 2015 · How do I prove this by induction? Prove that for every natural number n, $ 2^0 + 2^1 + ... + 2^n = 2^{n+1}-1$ Here is my attempt. Base Case: let $ n = 0$ Then, $2^{0+1} - 1 = …
summation - How can I define $e^x$ as the value of infinite series ...
Explore related questions summation exponential-function See similar questions with these tags.
summation - Sum of odd numbers always gives a perfect square ...
Explore related questions elementary-number-theory summation See similar questions with these tags.
summation - How to convert Sigma Notation to a regular formula ...
Sep 2, 2017 · $\\sum_{i=1}^n i$ is the same as $\\frac{n(n+1)}{2}$. Can someone explain how the sigma notation is converted to this? I'm trying to figure out if there's a way to convert …
How can we sum up $\sin$ and $\cos$ series when the angles are …
How can we sum up $\sin$ and $\cos$ series when the angles are in arithmetic progression? For example here is the sum of $\cos$ series: $$\sum_ {k=0}^ {n-1}\cos (a+k \cdot d) =\frac {\sin (n …
algebra precalculus - Rules for Product and Summation Notation ...
Feb 25, 2015 · Rules for Product and Summation Notation Ask Question Asked 12 years ago Modified 6 years, 1 month ago
summation - How to get to the formula for the sum of squares of …
The first chapter of Concrete Mathematics by Graham, Knuth, and Patashnik presents about seven different techniques for deriving this identity, so you might be interested to look at that.
summation - Intuition behind the formula for $\sum_ {i=1}^n i^ {2 ...
What is interesting is that your formula is the closed form for a different summation, i.e. $\displaystyle \sum_ {i=0}^n \binom {i+1}2=\sum_ {i=0}^n \frac {i (i+1)}2=\frac {n (n+1) …